Question

When 2-butyne is treated with $H_2$/Lindlar's catalyst, compound $X$ is produced as the major product and when treated with $Na/liq.N{H}_3$ it produced $Y$ as the major product. Which of the following statements is correct?
(1) $X$ will have higher dipole moment and higher boiling point than $Y$.
(2) $Y$ will have higher dipole moment and higher boiling point than $X$.

Answer 1

Lindlar catalyst gives Cis alkene while Na/liq.NH3 gives trans alkene.

Since dipole moment cis - > trans X > Y (dipole moment).

Boiling point is higher in case of cis product than trans product, because of

$\mu$ $cis$ $>$ $\mu$ $trans$ (dipole moment).

Hence, statement 1 is correct.