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Question

When 2 resistors are in parallel combination then determine i1 and i2, if the combination carries a current i ?

A
None
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B
i1=iR2R1 and i2=iR1R2
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C
i1=iR2R1+R2 and i2=iR1R1+R2
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D
i1=iR1R1+R2 and i2=iR2R1+R2
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Solution

The correct option is C i1=iR2R1+R2 and i2=iR1R1+R2Since, R1 and R2 are in parallel, so potential difference across them will be same. ∴i1R1=i2R2 ⇒i1i2=R2R1 ⇒i1+i2i2=R2+R2R1 Given: i=i1+i2 ∴ii2=R2+R2R1 ⇒i2=R1iR1+R2 Similarly, i1=R2iR1+R2 Hence, option (a) is correct. Why this question? Note:Remember this law of i∝1R in the resistor connected in parallel. It can be used in problems.

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