When 20 grams of sodium hydroxide is dissolved in 1 litre solution, find the normality of sodium hydroxide solution.
(Equivalent weight of $N a O H = 40$ )

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Solution

Mass of Sodium Hydroxide $= 20$ $g$

Equivalent Weight $= 40 u$

Volume of solution $= 1 L$

Or, $n -$ factor $= 1$

Then, $N o r m a l i t y = M o l a r i t y \times n - f a c t o r$

$= \frac{m a s s}{E q u i . W e i g h t} \times \frac{1000}{v o l u m e}$

$= \frac{20}{240} \times \frac{1000}{1} \times 1$

$= 500 N$

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When 20 grams of sodium hydroxide is dissolved in 1 litre solution, find the normality of sodium hydroxide solution.(Equivalent weight of NaOH=40)

Mass of Sodium Hydroxide =20 g Equivalent Weight =40 u Volume of solution =1 L Or, n−factor =1 Then, Normality=Molarity×n−factor =massEqui.Weight×1000volume =20240×10001×1 =500 N

When 20 grams of sodium hydroxide is dissolved in 1 litre solution, find the normality of sodium hydroxide solution.
(Equivalent weight of $N a O H = 40$ )