Question

When $200lit$ of water is subjected to a pressure of $2\times {10}^{5}Pa$. The decrease in its volume is $0.4\%$. The compressibility of water is.

• A. $2\times {10}^{-8}{m}^2{N}^{-1}$
• B. $5\times {10}^{-10}{m}^2{N}^{-1}$
• C. $5\times {10}^{-12}{m}^2{N}^{-1}$
• D. None

Answer 1

The correct option is A $2\times {10}^{-8}{m}^2{N}^{-1}$

We know that,

$\begin{array}{c}B=\frac{-P}{\Delta V/V}\\ \Rightarrow B=\frac{-2\times {10}^5}{-0.4/100}=\frac{20}{4}\times {10}^7=5\times {10}^{7}N/m^2\\ \text{compressibility}=\frac{1}{B}=2\times {10}^{-8}{m}^2{N}^{-1}\end{array}$