Question

When ${2222}^{5555}+{5555}^{2222}$ is divided by 7, the remainder is

• A. 2
• B. 4
• C. 5

Answer 1

${2222}^{5555}÷7\to 3^{5555}÷7\to 3^5÷7\to$ Remainder =5;
${5555}^{2222}÷7\to 4^{2222}÷7\to 4^2÷7\to$ Remainder =2.
Hence, the required remainder would be (5+2)/7 =0.