When 27 is divided by 4, the unique integers $q$ and $r$ as per Euclid's division lemma are and respectively.

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Solution

The correct options are
A 3
B 6
According to Euclid's division lemma, for positive $a$ and $b,$ there exist unique integers $q$ and $r$ such that
$a = b q + r,$ where $0 \leq r < b .$
We have $27 = 4 (6) + 3.$
Thus, on comparison, we get the quotient $q = 6$ and the remainder $r = 3.$

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When 27 is divided by 4, the unique integers q and r as per Euclid's division lemma are and respectively.

The correct options are A 3 B 6According to Euclid's division lemma, for positive a and b, there exist unique integers q and r such that a=bq+r, where 0≤r<b. We have 27=4(6)+3. Thus, on comparison, we get the quotient q=6 and the remainder r=3.

When 27 is divided by 4, the unique integers $q$ and $r$ as per Euclid's division lemma are and respectively.

The correct options are
A 3
B 6
According to Euclid's division lemma, for positive $a$ and $b,$ there exist unique integers $q$ and $r$ such that
$a = b q + r,$ where $0 \leq r < b .$
We have $27 = 4 (6) + 3.$
Thus, on comparison, we get the quotient $q = 6$ and the remainder $r = 3.$