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Head Elements (Group 1)

When 280 gm o...

Question

When 280 gm of ethylene polymerises to polyethene according to the equation.

$n C H_{2} = C H_{2} ⟶ - (C H_{2} - C H_{2})_{n} -$

The weight and mole of polyethylene formed will be:

280, 10n

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\frac{280}{n}

, n

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\frac{280}{n}

, 280

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280,

\frac{10}{n}

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Solution

The correct option is C 280, $\frac{10}{n}$
During polymerization of ethylene to polyethylene, no atoms are lost or added to ethylene. Thus, total mass of ethylene is equal to total mass of polyethylene. 280 gm of ethylene polymerises to give 280 gm of polyethylene.

The molar mass of ethylene is 28 g/mol. 280 gm of ethylene $= \frac{280 g}{28 g / m o l} = 10$ mol.

$n C H_{2} = C H_{2} polymerization - -------- \to (- C H_{2} - C H_{2} -)_{n}$
n moles of ethylene will give 1 mole and $n \times 28$ gm of polyethylene

10 moles of ethylene will give $\frac{10}{n}$ moles and $n \times 28 = 10 \times 28 = 280$ gm of polyethylene.

Option D is correct.

Suggest Corrections

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