When $2 s - 2 s, 2 p - 2 p$ and $2 p - 2 s$ orbitals overlap, the bond strength decreases in the order:

p - p > s - s > p - s

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p - p > p - s > s - s

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s - s > p - p > p - s

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s - s > p - s > p - p

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Solution

The correct option is A $p - p > p - s > s - s$
On the basis of extent of overlapping, greater the area of overlapping greater is the strength of bond. Since the area of overlapping is greatest in case of $p - p$ bond due to its dumbbell shape followed by $s - p$ & then $s - s$ .
Hence bond strength decreases in the order
$p - p > s - p > s - s$

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