When $3$ L of $0.5$ $M$ $N a C l$ is mixed with $9$ L of $0.2777$ $M$ $N a C l$ , determine the concentration of the final solution, assuming that volumes are additive?

0.33

M

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0.39

M

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0.5777

M

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0.7777

M

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None of the above

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Solution

The correct option is B $0.33$ $M$
Let $M$ and $V$ be the final molar concentration and final volume. $M_{1}$ and $V_{1}$ are the molar concentration and volume of $3$ L of $0.5$ $M$ $N a C l$ . $M_{2}$ and $V_{2}$ are the molar concentration and volume of $9$ L of $0.2777$ $M$ $N a C l$ .
$M V = M_{1} V_{1} + M_{2} V_{2}$
$M \times (3 + 9) L = 0.5 M \times 3 L + 0.2777 M \times 9 L$
$12 M = 1.5 + 2.5 = 4$
$M = \frac{4}{12} = 0.33$
Hence, the concentration of the final solution is $0.33$ $M$ .

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When 3 L of 0.5 M NaCl is mixed with 9 L of 0.2777 M NaCl, determine the concentration of the final solution, assuming that volumes are additive?

When $3$ L of $0.5$ $M$ $N a C l$ is mixed with $9$ L of $0.2777$ $M$ $N a C l$ , determine the concentration of the final solution, assuming that volumes are additive?