Question

When ${}_{3}L{i}^7$ nuclei are bombarded by protons and the resultant nuclei are ${}_{4}B{e}^8$, the emitted particles will be:

• A. alpha particles
• B. beta particles
• C. gamma particles
• D. neutrons

Answer 1

The correct option is C gamma particles

${}_{3}L{i}^7$ $+$$p$ $\to$ ${}_{4}B{e}^8$

When lithium of mass $7$ is bombarded with protons, the compound nucleus of beryllium is formed with mass $8$ . The proton captured by the lithium nucleus remains with the compound nucleus, beryllium, and the excess energy is emitted in the form of a gamma ray of $17MeV$ energy.