Question

When 3-methylbutan-2-ol is treated with HBr, the following reaction takes place. What are the correct steps for formation of the above product?

• A. Formation of carbocation $\to$ Nucleophilic attack by $B{r}^{\ominus }$
• B. Formation of carbocation $\to$ 1,2 hydride shift $\to$ Nucleophilic attack by $B{r}^{\ominus }$
• C. Formation of carbocation $\to$ 1,2 methyl shift $\to$ Nucleophilic attack by $B{r}^{\ominus }$
• D. None of these

Answer 1

The correct option is B Formation of carbocation $\to$ 1,2 hydride shift $\to$ Nucleophilic attack by $B{r}^{\ominus }$

The reaction (along with mechanism) for the conversion of 3-methylbutan-2-ol to 2-bromo-2-methylbutane is as given below.