Question

When $30\mu C$ charge is given to an isolated conductor of capacitance $5\mu F$ . Find energy stored in the electric field of conductor.

Answer 1

The energy stored in the capacitor is given as follows

$E=\frac{q^2}{2C}$

By substituting the values in the above given equation we get

$E=\frac{{\left(30\times {10}^{-6}\right)}^{2}C}{2\times 5\times {10}^{-6}F}$

$E=9\times {10}^{-5}J$

Hence the energy stored in the electric field of conductor is$E=9\times {10}^{-5}J$