When 30mL of 0.1 M standard solution of HCl is added to 15mL of NaOH solution to reach the endpoint then molarity of NaOH is:
A
0.1 M
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B
1 M
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C
0.3 M
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D
2 M
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E
0.2 M
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Solution
The correct option is E 0.2 M When 30mL of 0.1 M standard solution of HCl is added to reach the end point then, molarity of NaOH is 0.2 M. M1V1=M2V230×0.1=M2×15M2=0.2M