Question

When 340 g $N{H}_3$ (M = 17) decomposes, how many litres of nitrogen gas is produced at STP?

• A. 224 lit
• B. 112 lit
• C. 22.4 lit
• D. 448 lit

Answer 1

Answer: (A)

224 lit

Total moles of $N{H}_3$ = $\frac{340}{17}$ =20 moles

$2N{H}_3\to N_2+3H_2$

Now as we know that 1 mole of $N{H}_3$ produces 1/2 mole of $N_2$ gas, i.e., 11.2 liters of nitrogen gas.

20 moles of $N{H}_3$ will produce = 11.2$\times$20 = 224 litres.