Question

When $3A$ current is passed in a tangent galvanometer, there is a deflection of ${30}^o$ in it. The deflection obtained when $3\sqrt{3}$ ampere current is passed is

• A. ${30}^o$
• B. ${45}^o$
• C. ${60}^o$
• D. ${75}^o$

Answer 1

Answer: (B)

${45}^o$

$\frac{\tan {\theta }_1}{\tan {\theta }_2}=\frac{i_1}{i_2}$
$\frac{\tan {30}^o}{\tan {\theta }_2}=\frac{3}{3\sqrt{3}}$
$\tan \theta =1$
$\theta ={45}^o$