When $400 g$ of a $20 %$ Solution was cooled $50 g$ of the solute precipitated. What is the percent concentration of the remaining solution.

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Solution

Given:
weight of the solution = $400 g$
weight of the solute = $\frac{20 \times 400}{100}$ = $80 g$
weight of solute precipitated = $50 g$
weight of solute remained in the solution = $80 - 50 = 30 g$
weight of solution remained= $400 - 50 = 350 g$
Hence the percent concentration of the remaining solution= $\frac{30}{350 \times 100}$

$= 8.57$ % is the answer.

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When 400 g of a 20% Solution was cooled 50 g of the solute precipitated. What is the percent concentration of the remaining solution.

Given: weight of the solution =400gweight of the solute = 20×400100 = 80gweight of solute precipitated = 50gweight of solute remained in the solution = 80−50=30gweight of solution remained= 400−50=350gHence the percent concentration of the remaining solution=30350×100 =8.57 % is the answer.

When $400 g$ of a $20 %$ Solution was cooled $50 g$ of the solute precipitated. What is the percent concentration of the remaining solution.