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Question

When 400 ml of 0.2 M acetic acid is mixed with 800 ml of 0.5 M solution, NaOH of heat is liberated. The amount of heat utilised for complete dissociation of 4.416 KJ acetic acid is (0.3×y)KJ/mol. The value of ‘y’ is ___

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Solution

No of moles of solute =molarity×volumeofsolution

No. of moles of acid =0.2×400ml=80mmol

No. of moles of base =0.5×800ml=400mmol

CH3COOH+NaOHCH3COONa+H2O
80mmol400mmol80mmol
(For CH3COOH and NaOH mole and equivalent are the same because both have value of nfactor=1)

No. of equivalents of acid or base neutralised completely =80milieq.1000
801000 equivalents give 4.416 KJ
1 equivalent give 4.41680×1000=55.2kJ
heat of ionisation of CH3COOH=55.2+57.3=+2.1kJ/mole


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