Question

When ${}_{4}B{e}^9$ atom is bombarded with $\alpha -$ particles, one of the products of nuclear transmutation is ${}_6{C}^{12}$ .

• A. ${}_{-1}{e}^0$
• B. ${}_1{H}^1$
• C. ${}_1{D}^2$
• D. ${}_0{n}^1$

Answer 1

The correct option is D

${}_0{n}^1$

${}_{4}B{e}^9{+}_{2}H{e}^4{\to }_{6}B{e}^{12}{+}_0{n}^1$