When $5.0$ gram of $B a C l_{2}$ is dissolved in water to have $10^{6}$ gram of solution. The concentration of a solution is:

2.5 p p m

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5 p p m

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5 M

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5 g L^{- 1}

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Solution

The correct option is B $5 p p m$
As we know,
The concentration of solution (ppm) $= \frac{w t . o f s o l u t e}{w t . o f s o l u t i o n} \times 10^{6} = \frac{5}{10^{6}} \times 10^{6} = 5 p p m$

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When 5.0 gram of BaCl2 is dissolved in water to have 106 gram of solution. The concentration of a solution is:

The correct option is B 5 ppmAs we know,The concentration of solution (ppm) =wt.of solutewt.of solution×106=5106×106=5 ppm

When $5.0$ gram of $B a C l_{2}$ is dissolved in water to have $10^{6}$ gram of solution. The concentration of a solution is:

The correct option is B $5 p p m$
As we know,
The concentration of solution (ppm) $= \frac{w t . o f s o l u t e}{w t . o f s o l u t i o n} \times 10^{6} = \frac{5}{10^{6}} \times 10^{6} = 5 p p m$