When 50 cm3 of 0.2N H2So4 is mixed with 50 cm3 of 1 N KOH the heat liberated is (given H+(aq)+OH-(aq)gives H2O(l);del neutralizationH=-57.3kJ

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Q. When 50

{c m}^{3}

of 0.2 N

H_{2} {S O}_{4}

is mixed with 50

{c m}^{3}

of 1N KOH, the heat liberated is: (Given

H^{+} (a q) + {O H}^{-} (a q) \to H_{2} O (I); △_{n e u t} H = - 57.3 k J

)

At a particular temperature $H^{+} (a q) + O H^{-} (a q) \to H_{2} O (l); Δ H = - 57.1 k J$ . The approximate heat evolved when $400 m L$ of $0.2$ $H_{2} S O_{4}$ is mixed with $600 m L$ of $0.1 m$ $K O H$ solution will be:

Q. When

50 c m^{3}

0.2 N H_{2} S O_{4}

is mixed with

50 c m^{3}

1 N K O H

, the heat liberated is:

Q. When

{50 c m}^{3}

of 0.2 N

H_{2} {S O}_{4}

is mixed with

{50 c m}^{3}

of 1N KOH, the heat liberated is ?

Q. The volume of

0.2 N

H_{2} S O_{4}

mixed with

0.5 N K O H

(remaining volume) to prepare

150 c m^{3}

0.2 N K O H

solution is:

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