Question

When ${50cm}^3$ of 0.2 N $H_2{SO}_4$ is mixed with ${50cm}^3$ of 1N KOH, the heat liberated is ?

• A. 11.45 kJ
• B. 57.3 kJ
• C. 573 kJ
• D. 573 J

Answer 1

The correct option is D 573 J

$n$ of mole $H_{2}S{O}_4=0.05\times 0.2$

$={10}^{-2}$

$n$ of mole $KOH=0.05\times 1$

$0.05$

$=5\times {10}^{-2}$

$\therefore {10}^{-2}$ mole will react

$\Delta H_{ner}=57.3RJ/mol$

for ${10}^{-2}$ mol

Heat $=57.3\times {10}^3\times {10}^{-2}J$

$=573J$