When 50keV electrons are made to incident on a target material, the wavelength of Ka X-ray line was found to be 0.5˚A. When the accelerating potential is increased to 100kV, find the wavelength of Ka- line from the same target.
A
0.25˚A
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B
0.5˚A
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C
0.75˚A
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D
1.0˚A
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Solution
The correct option is A0.25˚A Wavelength, λ∝1V∴λV=constantλ1V1=λ2V2λ2=λ1V1V2=0.5×50k100k=0.25∘A