wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

When 5a2b+10b2c221ab+32 is subtracted from 5020b2c24bcac5ab, we get


A

18+30b2c24bcac+16ab5a2b+10b2c

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1830b2c24bcac+16ab5a2b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

2030b2c24bcac+16ab5a2b

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2230b2c24bcac16ab5a2b

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B: 1830b2c24bcac+16ab5a2b

We have

(5020b2c24bcac5ab)(5a2b+10b2c221ab+32)

=5020b2c24bcac5ab5a2b10b2c2+21ab32

=503220b2c210b2c2ac4bc5a2b+21ab5ab

=1830b2c2ac4bc5a2b+16ab

=1830b2c24bcac+16ab5a2b


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition and Subtraction of Algebraic Expression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon