When 9.65 C of electricity is passed through a solution of silver nitrate (atomic mass of Ag =108 g mol-1) the amount of silver deposited is:

16.2mg

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21.2mg

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10.8mg

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14.0mg

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Solution

The correct option is D 10.8mg

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Similar questions

When 9.65 coulombs of electricity is passed through a solution of silver nitrate (atomic weight of Ag = 107.3, approximately 108) the amount of silver deposited is:

When 9.65 coulombs of electricity is passed through a solution of silver nitrate

(atomic weight of taking as 108) the amount of silver deposited is

[EAMCET 1992; KCET 2000]

When 9.65 coulombs of electricity is passed through a solution of silver nitrate

(atomic weight of taking as 108) the amount of silver deposited is

[EAMCET 1992; KCET 2000]

Q. When

9.65

coulomb of electricity is passed through a solution of silver nitrate, the amount of silver deposited is:

Q. Find the mass of silver deposited when a current of 1.5 ampere is passed through silver nitrate solution for 5 min.

(Atomic mass of

A g

108

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