When $9$ Superscript two-thirds is written in the simplest radical form, which value remains under the radical?

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Solution

The mathematical expression of $9$ Superscript two-thirds:
Radical is the expression that contains a root.
It contains the value that has a fractional exponent.
The root can be a square root, cubic root, etc.
Solve as follows.
$9^{\frac{2}{3}} = {(9^{2})}^{\frac{1}{3}} = {(81)}^{\frac{1}{3}} = {(3 \times 3 \times 3 \times 3)}^{\frac{1}{3}} = 3 {(3)}^{\frac{1}{3}} = 3 \sqrt[3]{3}$
Hence, from the above expression, it is evident that $3$ is the value that is under the radical $(\sqrt[3]{3})$ .

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