Question

When ${{}_{92}U}^{235}$ bombarded by ${}_0{n}^1$ which one of the following is NOT obtained

• A. ${}_{54}{Xe}^{142}+{}_{38}{Sr}^{90}+4\left({}_0{n}^1\right)$
• B. ${}_{56}{Ba}^{139}+{}_{36}{Kr}^{94}+3\left({}_0{n}^1\right)$
• C. ${}_{55}{Cs}^{144}+{}_{37}{Rb}^{90}+2\left({}_0{n}^1\right)$
• D. ${}_{40}{Zr}^{94}+{}_{52}{Te}^{138}+3\left({}_0{n}^1\right)$

Answer 1

The correct option is D ${}_{40}{Zr}^{94}+{}_{52}{Te}^{138}+3\left({}_0{n}^1\right)$

${}_{92}U$ ${}^{235}+$${}_0{n}^1$${\to }_{92}U$${}^{236}$

(A)${}_{92}{U}^{236}$ $\to$ $5_{4}X{e}^{142}+$ ${}_{38}Sr$ ${}^{90}+4{(}_0{n}^1)$

(B)${}_{92}U$ ${}^{236}{\to }_{56}Ba$ ${}^{139}$+ ${}_{36}Kr$ ${}^{94}+3{(}_0{n}^1)$

(C)${}_{55}Cs$ ${}^{144}{\to }_{37}Rb$ ${}^{90}+2{(}_0{n}^1)$

In all these 3 fractions Atomic mass and

Atomic number is conserved.

(d)${}_{40}Zr$ ${}^{94}{+}_{52}Te$ ${}^{138}+3{(}_0{n}^1)$

In option 'd' Atomic mass is not conserved

therefore it can not be obtained.