When 92U235 undergoes fission. 0.1% of its original mass is changed into energy. 9×10xJ of energy is released if 1 kg of 92U235 undergoes fission. Value of x =
Given,
Mass defect = 0.1% of 1 kg
By using E = Δm.c2 where E = Energy, Δm = Mass defect, c = Speed of light
⇒E = (0.1100×1)(3×108)2 = 9×1013J.