When 92U235 undergoes fission, 0.1% of its original mass is changed into energy. 9×10xJ of energy is released if 1 kg of 92U235 undergoes fission, then the value of x =
Given,
Mass defect = 0.1% of 1 kg
By using E = Δm.c2, where E = Energy, Δm = Mass defect and c = Speed of light
⇒E = (0.1100×1)(3×108)2 = 9×1013J.