When $_{92} U^{235}$ undergoes fission. 0.1% of its original mass is changed into energy. How much energy is released if 1 kg of $_{92} U^{235}$ undergoes fission

9 \times 10^{10} J

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9 \times 10^{11} J

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9 \times 10^{12} J

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9 \times 10^{13} J

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Solution

The correct option is D $9 \times 10^{13} J$
By using $E = Δ m . c^{2} \Rightarrow E = (\frac{0.1}{100} \times 1) (3 \times 10^{8})^{2} = 9 \times 10^{13} J$

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When $_{92} U^{235}$ undergoes fission. 0.1% of its original mass is changed into energy. $9 \times 10^{x} J$ of energy is released if $1 k g$ of $_{92} U^{235}$ undergoes fission. Value of $x$ = ___

Q. When

^{92} U_{235}

undergoes fission 0.1% of its original mass is changed into energy. How much energy is released if 1 kg of

^{92} U_{235}

undergoes fission

Q. When

_{92} U^{235}

undergoes fission,

0.1 %

of its mass is converted into energy. How much mass of

_{92} U^{235}

will be required to produce

10 MJ

of energy?

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When 92U235 undergoes fission. 0.1% of its original mass is changed into energy. How much energy is released if 1 kg of 92U235 undergoes fission

The correct option is D 9×1013JBy using E=Δm.c2⇒E=(0.1100×1)(3×108)2=9×1013J

When $_{92} U^{235}$ undergoes fission. 0.1% of its original mass is changed into energy. How much energy is released if 1 kg of $_{92} U^{235}$ undergoes fission

The correct option is D $9 \times 10^{13} J$
By using $E = Δ m . c^{2} \Rightarrow E = (\frac{0.1}{100} \times 1) (3 \times 10^{8})^{2} = 9 \times 10^{13} J$