When a = 0, b = -1, find the value of the given expression:
$2 a^{2} + b^{2} + 1$

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Solution

$2 a^{2} + b^{2} + 1 = 2 (0)^{2} + (- 1)^{2} + 1$ [Putting a = 0, b =-1]
$= 2 \times 0 + 1 + 1 = 0 + 2 = 2$

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2 a^{2} + b^{2} + 1

Question 5 (ii)

When a = 0, b = -1, find the value of the given expression:
$2 a^{2} + b^{2} + 1$

a = 0, b = - 1

{2 a}^{2} + b^{2} + 1

When a = 0, b = − 1, find the value of the given expressions:

(i) 2a + 2b (ii) 2a²+ b² + 1

(iii) 2a²b + 2ab² + ab (iv) a² + ab + 2

a = 1

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c = 0

(a^{2} - b^{2}) + (c^{2} - b^{2}) + (a^{2} - c^{2})

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