When a = 0, b = -1, find the value of the given expression:
$2 a^{2} + b^{2} + 1$

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Solution

$2 a^{2} + b^{2} + 1 = 2 (0)^{2} + (- 1)^{2} + 1$ [Putting a = 0, b =-1]
$= 2 \times 0 + 1 + 1 = 0 + 2 = 2$

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Question 5 (ii)

When a = 0, b = -1, find the value of the given expression:
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