When $a = 0, b = - 1$ , find the value of the given expressions: $(i i) 2 a^{2} + b^{2} + 1$

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Solution

Find the value of the given expressions.
Substitute $a = 0, b = - 1$ in the given expression.
$∴ 2 a^{2} + b^{2} + 1 = 2 {(0)}^{2} + {(- 1)}^{2} + 1 \Rightarrow 2 a^{2} + b^{2} + 1 = 1 + 1 \Rightarrow 2 a^{2} + b^{2} + 1 = 2$
Hence, When $a = 0, b = - 1$ ,the value of the given expressions is $2$ .

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