When a 12Ω resistor is connected with a moving coil galvanometer, then its deflection reduces from 50 divisions to 10 divisions. The resistance of the galvanometer is
A
24Ω
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B
36Ω
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C
48Ω
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D
60Ω
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Solution
The correct option is C48Ω
Here. current ∝deflection
So, (i−ig)Rs=(ig)Rs(50k−10k)×12=10k×Rg 40×12=10×RgRg=48Ω