When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.
4800 Ω
Ohm’s Law states that, V=IR.
V or potential difference = 12V
I = 2.5 mA= 2.5 × 10−3 A so R = VI = 122.5 × 103 = 4800 Ω