When a 4 kg mass is hung vertically on a light spring obey's Hooks law , the spring stretches by 2 cms. The work required to be done by an external agent in stretching this spring by 5 cm will be ( g =9.8 ms−2 )
A
4.9 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.4 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.495 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.24 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!