Question

When a ball is $h$ meter high from a point $O$, its velocity is $v_0$. When it is $h$meter below $O$, its velocity is $2v_0$. Find the maximum height from $O$ it will acquire

• A. $\frac{2h}{3}$
• B. $\frac{5h}{3}$
• C. $\frac{3h}{2}$
• D. $2h$

Answer 1

The correct option is B $\frac{5h}{3}$

Using the third equation of motion,
$(2v{)}^2-v^2=2g(2h)$
$\frac{v^2}{2g}=\frac{2}{3}h$
$\Rightarrow h_{\text{max}}=h+\frac{2h}{3}=\frac{5h}{3}$