Question

When a ball is thrown up vertically with a velocity $v_0$ it reaches a height $h$. If one wishes to triple the maximum height then the ball be thrown with a velocity

• A. $\sqrt{3}{v}_0$
• B. $3v_0$
• C. $9v_0$
• D. $\frac{3}{2}{v}_0$

Answer 1

The correct option is A $\sqrt{3}{v}_0$

$CaseI:0=v_o^2-2ghorh=\frac{v_o^2}{2g}$
$CaseII:0=v_1^2-2g\left(3h\right)orh=\frac{v_1^2}{6g}$
so $\frac{v_1^2}{6g}=\frac{v_o^2}{2g}or{v}_1=\sqrt{3}{v}_o$