CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

When a ball is thrown up vertically with velocity $$ {v}_{o} $$ it reaches a maximum height of $$h$$. If one wishes to triple the maximum height then the ball should be thrown with velocity.


A
3v0
loader
B
3v0
loader
C
9v0
loader
D
32v0
loader

Solution

The correct option is A $$\displaystyle \sqrt{3}v_{0}$$
Maximum height means final velocity is zero.
Thus $$H=\dfrac{0-{u}^{2}}{-2g}=\dfrac{{u}^{2}}{2g}$$
To triple maximum height, i.e. 3H, we have, $$3H=\dfrac{{u'}^{2}}{2g}$$ or $${u'}^{2}=3{u}^{2}$$ or, $$u'=\sqrt{3} u$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image