Question

# When a ball is thrown up vertically with velocity $${v}_{o}$$ it reaches a maximum height of $$h$$. If one wishes to triple the maximum height then the ball should be thrown with velocity.

A
3v0
B
3v0
C
9v0
D
32v0

Solution

## The correct option is A $$\displaystyle \sqrt{3}v_{0}$$Maximum height means final velocity is zero.Thus $$H=\dfrac{0-{u}^{2}}{-2g}=\dfrac{{u}^{2}}{2g}$$To triple maximum height, i.e. 3H, we have, $$3H=\dfrac{{u'}^{2}}{2g}$$ or $${u'}^{2}=3{u}^{2}$$ or, $$u'=\sqrt{3} u$$Physics

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