When a ball is thrown upwards from top of the building, the time of ascend is 4s. Will it takes 4s to land at the bottom of the building? (since time of ascent =time of descend)

Open in App

Solution

No, In this case time of accent is not equal to descent.
Because height is not constant. Time of ascent when ball is thrown from the top of the building os 4 sec so time of descent is 4 sec to reach back at the top of the building but it take more than 4 second to reach the bottom of building.

Suggest Corrections

Similar questions

Time of ascend is equal to time of descend.

Does that mean a ball thrown vertically upwards from the top of a building takes the same time to ascend and descend?

H .

20 m

g = 10 m s^{- 2}

100 m

40 m s^{- 1}

100 m

40 {ms}^{- 1}

A ball is dropped from the top of a building of height hit with speed 50 m/s at bottom of the building. The time at which balls will meet is.

Join BYJU'S Learning Program