We use the fact that within an isolated uniformly magnetized ball,
→H′=−→J3, →B′=2μ0→J3, where →J is the magnetization vector. Then in a uniform magnetic field with induction →B0, we have by superposition,
→Bin=→B0+2μ0→J3, →Hin=→B0μ0−→J3
or, →Bin+2μ0→Hin=3→B0
also, →Bin=μμ0→Hin
Thus, →Hin=3→B0μ0(μ+2) and →Bin=3μ→B0μ+2