When a bar magnet is placed at 90 $^{0}$ to uniform magnetic field, it is acted upon by a couple which is maximum. For the couple to be half of the maximum value, it is to be inclined to the magnetic field at an angle is

30^{0}

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45^{0}

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60^{0}

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90^{0}

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Solution

The correct option is A $30^{0}$
$Z = m \times B$
$Z = m B s i n θ$
$Z_{1} = m B$
$Z_{2} = 2 = s i n θ$
$s i n θ = 0.5$
$θ = π / 6$
$= 30^{0}$

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When a bar magnet is placed at 900 to uniform magnetic field, it is acted upon by a couple which is maximum. For the couple to be half of the maximum value, it is to be inclined to the magnetic field at an angle is

The correct option is A 300Z=m×BZ=mBsinθZ1=mBZ2=2=sinθsinθ=0.5θ=π/6=300

When a bar magnet is placed at 90 $^{0}$ to uniform magnetic field, it is acted upon by a couple which is maximum. For the couple to be half of the maximum value, it is to be inclined to the magnetic field at an angle is

The correct option is A $30^{0}$
$Z = m \times B$
$Z = m B s i n θ$
$Z_{1} = m B$
$Z_{2} = 2 = s i n θ$
$s i n θ = 0.5$
$θ = π / 6$
$= 30^{0}$