When a bar magnet is suspended freely in a uniform magnetic field, identify the correct statements:

a) The magnet experiences only couple and undergoes only rotatory motion

b) The direction of torque is along the suspension wire

c) The magnitude of torque is maximum when the magnet is normal to the field direction

only a and c are correct

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only a and b are correct

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only b and c are correct

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a, b, c are correct

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Solution

The correct option is D a, b, c are correct
The bar magnet will only
experience a torque, It will not
experience any force
The direction of the torque will be
along the suspended wire according to
right hand thumbrule.
$\to z = \to m \times \to B$
$= m B s i n θ .$
And its magnitude will be maximum if $θ = 90$

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The correct option is D a, b, c are correctThe bar magnet will onlyexperience a torque, It will notexperience any forceThe direction of the torque will bealong the suspended wire according toright hand thumbrule.→z=→m×→B=mBsinθ.And its magnitude will be maximum if θ=90