When a bar magnet of magnetic moment 40 Am2 is placed in a magnetic field of induction 40 - 10-8 T- each pole experiences a force of 2 - 10-5 N- The distance between the two poles of the magnet is-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Magnetic Moment

When a bar ma...

Question

When a bar magnet of magnetic moment $40 A m^{2}$ is placed in a magnetic field of induction $40 \times 10^{- 8}$ T, each pole experiences a force of $2 \times 10^{- 5}$ N. The distance between the two poles of the magnet is:

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.8$ m
Force on a pole of a bar magnet in a magnetic field is given by:
$F = μ P$
$2 \times 10^{- 5} = 40 \times 10^{- 8} \times P$
$P = 50 A m$
Magnetic moment of a bar magnet is given by:
$M = P l$
$40 = 50 \times l$
$l = 0.8 m$

Suggest Corrections

Similar questions

Q. A bar magnet of magnetic moment

3.0 A - m^{2}

is placed in a uniform magnetic induction field of

2 \times 10^{- 5} T

. If each pole of the magnet experiences a force of

6 \times 10^{4} N

, the length of the magnet is

When a bar magnet of magnetic moment $¯ ¯¯¯¯ ¯ M$ is placed in a magnetic field of induction field strength $¯ ¯¯ ¯ B$ , each pole experiences a force of $¯ ¯¯ ¯ F$ then the distance between the South and North pole of the magnet measured inside it is :

A magnet of magnetic moment $1.525 \times 10^{- 3} A . m^{2}$ . is placed in a magnetic field of induction field strength $0.1 g a u s s$ , perpendicular to the field direction. Then each pole experiences a force of $0.305 d y n e s$ . The distance between the two poles of the magnet is

Q. A bar magnet of magnetic moment

3.0 A - m^{2}

is placed in a uniform magnetic induction field of

2 \times 10^{- 5} T

. If each pole of the magnet experiences a force of

6 \times 10^{4} N

, the length of the magnet is

Q. A bar magnet when placed at an angle of

30^{\circ}

to the direction of magnetic field induction of

5 \times 10^{- 2} T

, experiences a moment of couple

25 \times 10^{- 6} N - m

. If the length of the magnet is 5 cm its pole strength is

Join BYJU'S Learning Program

When a bar magnet of magnetic moment 40 Am2 is placed in a magnetic field of induction 40×10−8 T, each pole experiences a force of 2×10−5 N. The distance between the two poles of the magnet is:

The correct option is D 0.8 mForce on a pole of a bar magnet in a magnetic field is given by:F=μP2×10−5=40×10−8×PP=50AmMagnetic moment of a bar magnet is given by:M=Pl40=50×ll=0.8m

When a bar magnet of magnetic moment $40 A m^{2}$ is placed in a magnetic field of induction $40 \times 10^{- 8}$ T, each pole experiences a force of $2 \times 10^{- 5}$ N. The distance between the two poles of the magnet is:

The correct option is D $0.8$ m
Force on a pole of a bar magnet in a magnetic field is given by:
$F = μ P$
$2 \times 10^{- 5} = 40 \times 10^{- 8} \times P$
$P = 50 A m$
Magnetic moment of a bar magnet is given by:
$M = P l$
$40 = 50 \times l$
$l = 0.8 m$