when a block of mass M is suspended by a long wire of length L , the length of the wire becomes (L+l) . The elastic potential energy stored in the extended wire is ?

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When a block of mass M is suspended by a long wire of length L, the length of the wire becomes L+l. The elastic potential energy stored in the extended wire is

Q. When a block of mass

2 kg

is suspended by a long wire of length

1 m

, the length of wire becomes

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. The elastic potential energy stored in wire is
(Take

g = 10 m / s^{2}

)

Q. When a block of mass

2 kg

is suspended by a long wire of length

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, the length of wire becomes

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. The elastic potential energy stored in wire is
(Take

g = 10 m / s^{2}

)

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× stress × strain × volume. Show that it is equal to

\frac{1}{2}

Mgl, where l is the extension. The loss in gravitational potential energy of the mass earth system is Mgl. Where does the remaining

\frac{1}{2}

Mgl energy go?

Q. When a body of mass

M

is attached to lower end of a wire having length

l

and upper end is fixed, then elongation of the wire is

l

. In this situation, mark out the correct statement(s).

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