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Question

When a body falls from rest its distance from the starting point varies as the square of the time it has been falling : if a body falls through 40212 feet in 5 seconds, how far does it fall in 10 seconds? Also how far does it fall in the 10th second?

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Solution

Let d be the distance from starting point and t be the time, then according to question

d=kt2

Given d=402.5 for t=5. So,

402.5=k.52

k=402.525=16.1

So,

d=(16.1)t2

For t=10

d=(16.1)100=1610 feets

and distance for t=9

d=(16.1)81=1304.1 feets

Distance fallen in 10th second =distance at t=10 - distance at t=9

=16101304.1=305.9 feets

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