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Question

When a body is suspended to a spring its length is increased by 0.2 m, then the same body is further pull down by 5 cm and released. Its time period of oscillation is :

A
8 s
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B
0.9 s
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C
7 s
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D
3.14 s
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Solution

The correct option is B 0.9 s
In the initial condition,

kx=mg ; Given, x=0.2m

So, we have

k×0.2=m×10

mk=0.02

T=2πmk

T=2π0.02

T=0.9 s

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