Question

When a body is thrown with a velocity $u$ making an angle $\theta$ with the horizontal plane, the maximum distance covered by it in horizontal direction is

• A. $\frac{u^2\sin \theta }{g}$
• B. $\frac{u^2\sin 2\theta }{g}$
• C. $\frac{u^2\sin 21\theta }{g}$
• D. $\frac{u^2\cos \theta }{g}$

Answer 1

The correct option is B $\frac{u^2\sin 2\theta }{g}$

Horizontal velocity=$ucos\theta$

Time t=$\frac{2usin\theta }{g}$

Maximum horizontal distance = Range=horizontal velocity × t=$\frac{u^{2}sin2\theta }{g}$