Question

When a body moves through still water at a constant velocity of 4.5 m/s, the velocity of water at 0.8 m ahead of the nose of the body is 3.0m/s. What will be the difference in pressure between the nose and the difference in pressure between the nose and the point 0.8 m ahead of it?

• A. $875N/m^2$
• B. $1000N/m^2$
• C. $1125N/m^2$
• D. $5625N/m^2$

Answer 1

The correct option is D $5625N/m^2$

$\frac{P_1-P_2}{\rho g}=\frac{V_2^2-V_1^2}{2g}$

$P_1-P_2=\frac{1000}{2}[{4.5}^2-3^2]$

$=500[{4.5}^2-3^2]$

$=5625N/m^2$