When a body of mass M slides down an inclined plane of inclination - having coefficient of friction - through a distance s- the work done against friction is-

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Standard XII

Physics

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When a body o...

Question

When a body of mass $M$ slides down an inclined plane of inclination $θ$ , having coefficient of friction $μ$ through a distance $s$ , the work done against friction is:

(μ M g cos θ) s

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(μ M g sin θ) s

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M g (μ cos θ - sin θ) s

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None of the above

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Solution

The correct option is A $(μ M g cos θ) s$
$N = M g c o s θ$
Frictional force = $μ M g c o s θ$
Work done against friction= $- F r i c t i o n a l f o r c e \times s = μ M g c o s θ s$

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When a body of mass M slides down an inclined plane of inclination θ, having coefficient of friction μ through a distance s, the work done against friction is:

The correct option is A (μMgcosθ)sN=MgcosθFrictional force =μMgcosθWork done against friction=−Frictionalforce×s=μMgcosθs

When a body of mass $M$ slides down an inclined plane of inclination $θ$ , having coefficient of friction $μ$ through a distance $s$ , the work done against friction is:

The correct option is A $(μ M g cos θ) s$
$N = M g c o s θ$
Frictional force = $μ M g c o s θ$
Work done against friction= $- F r i c t i o n a l f o r c e \times s = μ M g c o s θ s$