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Question

When a body of mass M slides down an inclined plane of inclination θ, having coefficient of friction μ through a distance s, the work done against friction is:

A
(μMgcosθ)s
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B
(μMgsinθ)s
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C
Mg(μcosθsinθ)s
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D
None of the above
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Solution

The correct option is A (μMgcosθ)s
N=Mgcosθ
Frictional force =μMgcosθ
Work done against friction=Frictionalforce×s=μMgcosθs

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